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mparison:  3y + 2 ? y | | 5  Then simplify:  Step 1: Multiply both sides by 5 to get  3y + 2?5y | |  Step 2: Subtract 3y from both sides to get  2?2y | |  Step 3: Divide both sides by 2 to get  1 ? y | |  The comparison is now simplifified as much as possible. In order to compare 1  and y, note that you are given the information (above Quantities A and B). y > 4  It follows from that or so that in the comparison the y > 4 y > 1, 1 < y, 1? y, | |  placeholder represents ? 1 less than (<): < y. | |  However, the problem asks for a comparison between Quantity A and  Quantity B, not a comparison between 1 and y. To go from the comparison  between 1 and y to a comparison between Quantities A and B, start with the last  comparison, and carefully consider each simplifification step in reverse 1 < y,  order to determine what each comparison implies about the preceding  comparison, all the way back to the comparison between Quantities A and B if  possible. Since step 3 was “divide both sides by 2,” multiplying both sides of the  comparison by 2 implies the preceding comparison thus reversing 1 < y 2 < 2y,  step 3. Each simplifification step can be reversed as follows:  ! Reverse step 3: multiply both sides by 2.  ! Reverse step 2: add 3y to both sides.  ! Reverse step 1: divide both sides by 5.  When each step is reversed, the relationship remains less than

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